Home » 1 » 2 » answers » functions » math » module » quadratic » secondary » 55 Secondary Math 2 Module 1 Quadratic Functions 1.2 Answers

55 Secondary Math 2 Module 1 Quadratic Functions 1.2 Answers

Module 1 quadratic functions
Module 1 quadratic functions from www.slideshare.net

Introduction

Welcome to the world of Secondary Math 2! In this module, we will be diving into the fascinating world of quadratic functions. In particular, we will be exploring Module 1, where we will be focusing on quadratic functions and their properties. In this article, we will be providing the answers to the exercises in Secondary Math 2 Module 1 Quadratic Functions 1.2. So, let's get started and unlock the secrets of quadratic functions together!

Exercise 1

To begin our journey, let's take a look at Exercise 1 of Secondary Math 2 Module 1 Quadratic Functions 1.2. This exercise asks us to find the vertex form of the quadratic function given certain information. Let's break it down step by step:

  1. Step 1: Identify the vertex form of a quadratic function. The vertex form of a quadratic function is given by the equation y = a(x - h)^2 + k, where (h, k) represents the vertex of the parabola.
  2. Step 2: Determine the vertex. In this exercise, the vertex is given as (2, -3).
  3. Step 3: Substitute the values into the vertex form equation. Plugging in the values, we get y = a(x - 2)^2 - 3.
  4. Step 4: Simplify the equation. We can further simplify the equation by expanding the square term, which gives us y = a(x^2 - 4x + 4) - 3.

So, the answer to Exercise 1 of Secondary Math 2 Module 1 Quadratic Functions 1.2 is y = a(x^2 - 4x + 4) - 3.

Exercise 2

Now, let's move on to Exercise 2 of Secondary Math 2 Module 1 Quadratic Functions 1.2. This exercise asks us to determine the vertex and axis of symmetry of a given quadratic function. Let's break it down:

  1. Step 1: Identify the vertex form of a quadratic function. As mentioned earlier, the vertex form of a quadratic function is given by y = a(x - h)^2 + k.
  2. Step 2: Determine the vertex. In this exercise, we are given the equation y = 3(x + 2)^2 - 5. By comparing this equation to the vertex form, we can see that the vertex is (-2, -5).
  3. Step 3: Find the axis of symmetry. The axis of symmetry is a vertical line that passes through the vertex of the parabola. In this case, the equation of the axis of symmetry is x = -2.

So, the answer to Exercise 2 of Secondary Math 2 Module 1 Quadratic Functions 1.2 is the vertex (-2, -5) and the axis of symmetry x = -2.

Exercise 3

Let's move on to Exercise 3 of Secondary Math 2 Module 1 Quadratic Functions 1.2. This exercise asks us to determine the vertex and axis of symmetry of a given quadratic function. Let's break it down:

  1. Step 1: Identify the vertex form of a quadratic function. Again, the vertex form of a quadratic function is given by y = a(x - h)^2 + k.
  2. Step 2: Determine the vertex. In this exercise, we are given the equation y = 2(x - 3)^2 + 1. By comparing this equation to the vertex form, we can see that the vertex is (3, 1).
  3. Step 3: Find the axis of symmetry. The axis of symmetry is a vertical line that passes through the vertex of the parabola. In this case, the equation of the axis of symmetry is x = 3.

So, the answer to Exercise 3 of Secondary Math 2 Module 1 Quadratic Functions 1.2 is the vertex (3, 1) and the axis of symmetry x = 3.

Exercise 4

Let's move on to Exercise 4 of Secondary Math 2 Module 1 Quadratic Functions 1.2. This exercise asks us to determine the vertex and axis of symmetry of a given quadratic function. Let's break it down:

  1. Step 1: Identify the vertex form of a quadratic function. Once again, the vertex form of a quadratic function is given by y = a(x - h)^2 + k.
  2. Step 2: Determine the vertex. In this exercise, we are given the equation y = -4(x + 1)^2 + 7. By comparing this equation to the vertex form, we can see that the vertex is (-1, 7).
  3. Step 3: Find the axis of symmetry. The axis of symmetry is a vertical line that passes through the vertex of the parabola. In this case, the equation of the axis of symmetry is x = -1.

So, the answer to Exercise 4 of Secondary Math 2 Module 1 Quadratic Functions 1.2 is the vertex (-1, 7) and the axis of symmetry x = -1.

Exercise 5

Now, let's move on to Exercise 5 of Secondary Math 2 Module 1 Quadratic Functions 1.2. This exercise asks us to determine the vertex and axis of symmetry of a given quadratic function. Let's break it down:

  1. Step 1: Identify the vertex form of a quadratic function. As mentioned earlier, the vertex form of a quadratic function is given by y = a(x - h)^2 + k.
  2. Step 2: Determine the vertex. In this exercise, we are given the equation y = -2(x - 4)^2 - 3. By comparing this equation to the vertex form, we can see that the vertex is (4, -3).
  3. Step 3: Find the axis of symmetry. The axis of symmetry is a vertical line that passes through the vertex of the parabola. In this case, the equation of the axis of symmetry is x = 4.

So, the answer to Exercise 5 of Secondary Math 2 Module 1 Quadratic Functions 1.2 is the vertex (4, -3) and the axis of symmetry x = 4.

Exercise 6

Let's move on to Exercise 6 of Secondary Math 2 Module 1 Quadratic Functions 1.2. This exercise asks us to determine the vertex and axis of symmetry of a given quadratic function. Let's break it down:

  1. Step 1: Identify the vertex form of a quadratic function. Again, the vertex form of a quadratic function is given by y = a(x - h)^2 + k.
  2. Step 2: Determine the vertex. In this exercise, we are given the equation y = 5(x - 2)^2 + 4. By comparing this equation to the vertex form, we can see that the vertex is (2, 4).
  3. Step 3: Find the axis of symmetry. The axis of symmetry is a vertical line that passes through the vertex of the parabola. In this case, the equation of the axis of symmetry is x = 2.

So, the answer to Exercise 6 of Secondary Math 2 Module 1 Quadratic Functions 1.2 is the vertex (2, 4) and the axis of symmetry x = 2.

Exercise 7

Let's move on to Exercise 7 of Secondary Math 2 Module 1 Quadratic Functions 1.2. This exercise asks us to determine the vertex and axis of symmetry of a given quadratic function. Let's break it down:

  1. Step 1: Identify the vertex form of a quadratic function. Once again, the vertex form of a quadratic function is given by y = a(x - h)^2 + k.
  2. Step 2: Determine the vertex. In this exercise, we are given the equation y = -3(x + 3)^2 - 2. By comparing this equation to the vertex form, we can see that the vertex is (-3, -2).
  3. Step 3: Find the axis of symmetry. The axis of symmetry is a vertical line that passes through the vertex of the parabola. In this case, the equation of the axis of symmetry is x = -3.

So, the answer to Exercise 7 of Secondary Math 2 Module 1 Quadratic Functions 1.2 is the vertex (-3, -2) and the axis of symmetry x = -3.

Exercise 8

Now, let's move on to Exercise 8 of Secondary Math 2 Module 1 Quadratic Functions 1.2